Question

a mine shaft is being drilled from the surface using a method that processes downward through the rock the same amount each day.in a 6day period the drill went from -10m to -46m.what integer shall represent the drill's position relative to the surface afternoon 25 days.....find out this plzzz urgent.....​

Answer 1

After 25 days, the drill will be at -160 m from surface

Step-by-step explanation:

Position change = -10m to -46m

Time= 6 days

So 1 day change in position = [-10-(-46)]/6 =36/10 =6 m (Since its uniform)

So after 25 days, the drill's position will be = -10- 25*6

=-10-150 =-160m

Answer 2

Answer:

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