A mineral contained Mgo=31.8,sio²=63.37 and h²o=4.75.Calculate the simplest formula for the mineral.(Atomic weight :Mg=24,si=28
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Answer:
Assuming, total mass of compound = 100gm
Hence, mass of MgO = 31.88gm, mass of SiO
2
= 63.37gm and mass of H
2
O=4.75gm.
Since, moles=
molecular mass of compound
mass of compound
So, moles of MgO =
40
31.88
= 0.8 moles of SiO
2
=
60
63.37
=1.05moles of H
2
O=
18
4.75
=0.26
Hnece, the mole ratio = MgO : H
2
O:SiO
2
=3:1:4
Hence, minimum moles of H
2
O=1,MgO=3 and SiO
2
=4
Hence, simplest formula => H
2
O.3MgO.4SiO
2
=H
2
Mg
3
Si
4
O
12
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