Question

A Mini Cooper of mass 1350kg is traveling at a speed of. 100km/h and travels a distance if 45 m before coming to rest. Determine the magnitude of the net force required to bring the machine to rest and state the direction with regards to initial velocity

Answer 1

Answer:11574

Explanation:u=500/18m/s,s=45m

By this we can find acceleration of car2as=V2-u2and v means final velocity is zero a=25000/2916 and force =acceleration mul. Mass of object i.e. 11574and in opposite directions

Answer 2

Answer:

The force is $1485\times 10^{5}N$.

Explanation:

Given:

u = 100Km/h

S = 0.045Km

m = 1350Kg

v = 0Km/hr

Here,

The force is denoted by F.

The mass of mini cooper is dedenoted by m.

The distance is denoted by S.

The retarding acceleration is denoted by a.

The initial speed is denoted by u.

The final velocity is denoted by v.

Now,

By the equation,

$v^{2} =u^{2} -2as\\0^{2} =100^{2} -2\times a\times 0.045\\a=1.1\times 10^{5}Km/hr^{2}$

Then,

By the equation,

$F=ma\\F =1350\times 1.1\times 10^{5}\\F=1485\times 10^{5}N$

To stop the mini cooper, the direction of force is opposite to the direction of the initial velocity.

So, the force is $1485\times 10^{5}N$.