A mini truck can bear at most 710 kg of weight. Sixteen bags of various weights are kept in the truck. Exactly one bag weighs 71 kg, which is the maximum weight of the bags in the mini-truck. Exactly one bag weighs 'X' kg, which is the minimum weight. Which of the following can be the value of 'X'? Assume that the weight of each bag is an integer.
Answers
Step-by-step explanation:
answer- 41
this is a perfect explanation.
Given:
A mini truck can bear at most 710 kg of weight.
Sixteen bags of various weights are kept in the truck.
71 kg is the maximum weight of the bags.
'X' kg is the minimum weight.
To find:
The minimum weight of the bag in the truck
Solution:
Weight of remaining bags except
maximum and minimum weight bags = 710 - 71 - X
= 639 - X
Weight of other 14 bags can be (X + 1) kg
14(X + 1) ≤ 639 - X
14X + 14 ≤ 639 - X
15X ≤ 625
X ≤ 41.67 or X ≤ 41
X ≠ 41.67 since it is not integer
For X = 41 , total weight of 14 bags = 710 -71 - 41 = 598 kg
14(X + 1) = 14(42) = 588 kg
598 > 588
Hence, the minimum weight of the bag in the truck is 41 kg.