Question

A minibus can take 9 passengers.
What is the smallest number of minibuses needed to seat 1055 passengers?

Answer 1

Answer:

118

Step-by-step explanation:

as one minibus (m) can take 9 passengers (p) so

1m=9p

xm=1055 here xm stand for total buses

by cross multiplication

9x=1055×1

X=1055÷9

X= 117.22

as minibuses cannot be in fraction or decimal so we will round off 117.22 to 118

and our final answer is that 1055 passengers will be seated in 118 mini buses.

Answer 2

sorry I don't know

really sorry