Math, asked by shivulingappa086, 5 months ago

A mint moulds four types of copper coin A,B,C,D whose diameter vary from 0.5cm to 5cm. The first coin A has a diameter of 0.7cm. the second coin B has double the diameter of a coin A and from then onwards the diameter uncreas by 50% thickness of coin is 0.25cm​

Answers

Answered by itsbiswaa
21

As the coins are in the form of thin cylinder

Volume of each coin = π×(0.75)²×0.2 =0.1125π cm³

Volume of melted cylinder = π× (2.25)²× 10 = 50.625π cm³

number of coin required = (volume of melted cylinder)/(volume of each coin)

= 50.625π/0.1125π = 450 coins

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Answered by mahendrasinghdhoni19
3

Answer:

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