Question

A miopic perosn uses a lense of power -1.25d what is its far point

Answer 1

Answer:

Power=-1.25D

P=100/f(cm

1.25=100/f

f=100/-1.25

f=-80 cm

focal length=-80 cm

It is a concave lens

v=?

u=-25cm

1/f=1/v-1/u

1/f+1/u=1/v

-1/80-1/25=1/v

-5/400-16/400=1/v

-21/400=1/v

v=-400/21

v=-19.047

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