If Ab=67cm and ad=41cm and CD=58cm
find the area of the trapezium in m2
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The area of the trapezium is 2500 cm^2
Step-by-step explanation:
Given data:
- AB = 67 cm
- CD = 58 cm
- AD = 41 cm
EB = CD = 58 cm ----- (1)
AE = AB − EB
= (67 − 58) cm =9 cm
Now angle DEA = 90°
(DE)^2 = ( AD)^ 2 − (AE)^ 2 = (41)^ 2 - (9)^ 2
= 1681 − 81 = 1600
DE= 1600 =40 cm
DE = 40 cm ----- (2)
Total area = Area of triangle + Area of rectangle
= 1/2 AE x DE + DC x C.B
= 1/2 (9) x (40) + (58) x (40)
= (9) x (20) + (58) x (40)
= 180 + 2320
= 2500 cm^2
Hence the area of the trapezium is 2500 cm^2
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