A mirror forms a 6cm tall image of a 2cm object in the other side of a mirror . If the radius of curvature of the mirror is 50cm , calculate the focal length of the mirror.
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magnification = -v/(-u) = height of image/height of object =6/2 = 3
and also radius of curvature= 50cm
f = R /2 = 50/2 = 25cm
because image is magnify only concave mirror so, f = -25cm
v = 3u ----(1)
use mirror formula,
1/u + 1/v = 1/f
1/u + 1/(3u) = 1/(-25)
4/3u = -1/25 cm
u =- 100/3 cm
v = 100 cm
and also radius of curvature= 50cm
f = R /2 = 50/2 = 25cm
because image is magnify only concave mirror so, f = -25cm
v = 3u ----(1)
use mirror formula,
1/u + 1/v = 1/f
1/u + 1/(3u) = 1/(-25)
4/3u = -1/25 cm
u =- 100/3 cm
v = 100 cm
WRONG ANSWER
how , focal length = -25cm
ook ur right
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