Question

a mixture consists of 44 5/11% sand , 36 4/11% gravel and the rest is cement .Find the mass of mixture thta contains 12.5 kg of sand and also the mass of mixture that will contain 4 kg of cement​

Answer 1

Answer:

Let the mixture be 100%

Quantity of sand in the mixture =

11

500

%

Quantity of gravel in the mixture =

11

400

%

Quantity of Cement in the mixture =100%−

11

500

%−

11

400

%

⇒

11

1100÷500−400

%

⇒

11

200

%

Let xKg of mixture contain 12.5Kg of sand

But 100% of mixture contains

11

500

% of sand

⇒

100%

x

=

11

500

%

12.5

⇒x=

500%

12.5×100%

×11Kg

=2.5×11kg

=27.5Kg

let yKg of mixture contain 4Kg of cement

But 100% of mixture contain

11

200

% discount

⇒

100%

y

=

11

200

%

4

y=22Kg