Question

Rajesh starts his job with a monthly salary of ₹20,000 and he get a fixed annual increment of ₹4000. What will be his salary 10th years? *

Answer 1

Answer:

20000 multiply 10 = 200000

next step

200000/40000 = 5

40000+20000

= 60000

Answer 2

Given,

Initial monthly salary of Rajesh = Rs. 20,000

Fixed annual increment = Rs. 4,000

To find,

Salary of Rajesh in the 10th year.

Solution,

We can simply solve this mathematical problem by using the following mathematical process :

Per year increase in salary of Rajesh = Rs. 4,000

This implies that, after n-th years from the initial year of the job, the total increase in the initial salary can be calculated as follows;

Total increment in the initial salary, in after "n" years from the initial year = Rs. (n x 4000)

Now, the total increment in the initial salary, in the 10th year from the initial year = Rs. (10 x 4000)

= Rs. 40,000

So,

The total salary of Rajesh in the 10th year

= Initial salary + total increment in the initial

salary

= Rs. 20,000 + Rs. 40,000

= Rs. 60,000

Hence, the total salary of Rajesh in the 10th year is Rs. 60,000.