Question

A mixture consists of 45% sand, 36% gravel and rest cement. Find the weight of
mixture which contains 12.5 kg wt of sand. Also determine the weight of mixture that will
contain 4 kg wt of cement.​

Answer 1

Answer:

y=22 kg

Step-by-step explanation:

Let the mixture be 100%

Quantity of sand in the mixture= 500%/11                                                                                

Quantity of gravel in the mixture =   400  %/11

Quantity of Cement in the mixture =100%-500/11%-400/11%

=>1100 divide by 500-400

--------------------------------------%

            11

=>200

 ----------%

 11

Let x Kg of mixture contain 12.5 Kg of sand

But 100% of mixture contains 500/11% of sand

x/100%=12.5

             -------------

          500/11%

x=12.5×100%/500%

12.5×100%  ×11 Kg

=2.5×11 kg

=27.5 Kg

let y Kg of mixture contain 4 Kg of cement

But 100% of mixture contain   200 /11% discount

y/100%=4/200/11%

y=22 kg

i am using laptop so[ / ]means divide by

 

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Answer 2

Answer:

hiii thank you so much

Step-by-step explanation:

what is your name