Question

A mixture containing 1.0 mol H2(g), 7.0 mol N2(g), and 2.0 mol O2(g) experts a total pressure of 1.5 atm. What is the partial pressure of the O2(g)?

Answer 1

Answer:

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Explanation:

Given:

V=1L

T=273K

Let us find the Partial pressure of O2.

No. of moles =4/32=0.125moles

P1 =vnRT= 0.125×0.082×1273=2.80atm

Now let us find the partial pressure of H2.

P2= vnRT=1×0.082×1273=22.386atm

Total pressure of the mixture = 2.80+22.38=25.18atm.

Therefore 25.18≈ 25.21

by:︻╦デ╤━╼ADITYA ╾━╤デ╦︻