Question

A mixture contains 16g of oxygen and 28g of nitrogen 8g of methane

Answer 1

Kya karna h iska reaction

Answer 2

Answer:

370 mm

Explanation:

as no of moles of o2=16/32=0.5 moles

no of moles of n2=28/28=1 moles

no of moles of ch4=8/16=0.5 moles

total pressure=740mm

partial pressure=total pressure*mole fraction of n2

mole fraction of n2=no of moles of n2/total no of moles

=1/0.5+0.5+1=1/2

then partial pressure=1/2*740

=370 mm