Question

a mixture contains 20 mole of N2 and 80 of O2 percentage by mass of O2 in the mixture​

Answer 1

Answer:

% by mass of O2=(no. Of moles of O2/No. Of moles of N2 + that of O2 )×100

Explanation:

=(80/20+80)

=(80/100)×100

=80%

Plz.. Hit me up