Question

A mixture contains A and B in the ratio 5:7. 24 litres of this mixture is taken out and 15 litres of A is poured in. Now the ratio of A to B becomes 10:7. Find the amount of B originally present in the mixture

Answer 1

Answer:

The amt. of B in sol.=35 L

Step-by-step explanation:

Sum of the ratios= 5+7=12

Now, after adding 15 l of a in sol.= (5/12)×24 + 15=10 + 15= 25 L

Let  the amt. of B in sol. be X

∴25:X= 5:7

⇒X= (7/5)×25=7×5=35 L

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