Question

A mixture contains alcohol and water in the
ratio 3:2. If 4 litres of water is added to the
mixture, the ratio becomes 3 : 4. Find the
quantity of water in the given mixture.​

Answer 1

Given,

A mixture contains alcohol and water in the  ratio 3:2. If 4 litres of water is added to the  mixture, the ratio becomes 3 : 4.

To find :

Find the  quantity of water in the given mixture.​

Solution :

Let the quantity of alcohol be 3m and quantity of water be 2m

Now when 4 liters of water is added ratio becomes 3 : 4

So atq,

⇒ 3m : (2m + 4) = 3 : 4

⇒ 3m/(2m + 4) = 3/4

⇒ 12m = 3(2m + 4)

⇒ 12m = 6m + 12

⇒ 12m - 6m = 12

⇒ 6m = 12

⇒ m = 12/6

⇒ m = 2

Now quantity :

⇒ Quantity of alcohol = 3m = 3(2) = 6 liters.

⇒ Quantity of water = 2m = 2(2) = 4 liters.

Therefore,

Quantity of water in the given mixture = 4 liters.

Answer 2

Answer: Quantity of water in mixture is 4 litre.

Concept : Ratio and Proportion

Given : A mixture contains alcohol and water in the ratio of 3:2. If 4 l of

            water is added, the ratio becomes 3:4.

To Find : Quantity of water in the given mixture.

Step-by-step explanation:

Let the common ratio be x.

∴ The quantity of alcohol is 3x and quantity of water is 2x.

According to the question :

Now, when 4 liters of water is added ratio becomes 3 : 4.

⇒ 3x : (2x + 4) = 3 : 4

⇒ $\frac{3x}{2x + 4} = \frac{3}{4}$

⇒ $\frac{x}{x + 4} = \frac{1}{4}$

⇒ 4x = 2x + 4

⇒ 2x = 4

∴ x = 2

∴ Quantity of water in mixture = 2x = 2* 2 = 4 litre

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