Question

A mixture contains equal masses of seo and seo2 the total pressure of the mixture was found to be 54 atm then partial pressure of seo will be

Answer 1

Answer:

Explanation:

∵ A mixture contains equal masses of seo and seo2.

   The total pressure of the mixture is  54 atm

We have to find the partial pressure of seo

At, first we have to calculate the mole fraction of seo in the mixture.

$mole fraction of seo = \frac{number of moles of seo}{number of moles of seo + number of moles of seo2}$

Since , the given weight is same for seo and seo2

Let the respected weighr of both the substance be w;

∴ Total moles of seo will be w/96

and total moles of seo2 will be w/192

$mole fraction of seo = \frac{w/96}{w/96 + w/192}$

=$\frac{w}{96}  \times \frac{192}{3w}$

= 2/3

Hence, the mole fraction of seo is 2/3

Now, we have to calculate partial pressure of seo ;

∴$partial pressure of seo = Total pressure \times mole fraction$

partial pressure of seo =$54 atm \times \frac{2}{3}$

= 36 atm

So, the partial pressure of seo will be 36 atm