Question

A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5 how many liters of latter must be mixed with 3 liters of the former so that the resulting mixture may contain equal quantities of wine and water

Answer 1

Answer:

Step-by-step explanation:The first mixture contains wine and water in the ratio of 3:2

=> 3 liters of first mixture has 1.8 liters of wine and 1.2 liters of water. (To maintain the 3:2 ratio)

Let us say that the first mixture is mixed with the second mixture that has quantity as 9x liters (4x liters of wine and 5x liters of water).

After mixing,

Total quantity of wine = Total quantity of water

=> 1.8 + 4x = 1.2 + 5x

=> x = 0.6 liters

=> 9x = 9*0.6 = 5.4 liters

We need 5.4 liters of second mixture to get equal quantities of water and wine

Answer 2

former equation,
3:2
3x+2x=3
x=3/5
water=9/5
wine=6/5
later equation,
4:5
so amount of water=4x
amount of wine=5x
a.t.q
9/5 +4x=6/5 +5x
(9+20x)/5=(6+25x)/5
3=5x
x=3/5
total mixture in later equation is
4x+5x=9x=9×3/5=27/5=5.4l