Math, asked by dhakadrohit8858, 1 year ago

. a mixture has milk and water in the ratio 5:1. 20 liters of water is added and the ratio now becomes 5:6. how much milk was present in original mixture?

Answers

Answered by anex999
0
as it is in ratio of 5:1 
so 
5x+1x= 6x
after 20 l of water is added 
5x+6x= 11x

diff.. 11x-6x=20 l
or
11x- 6x= 5x
so 
5x=20l
x=20/5
x= 4
fron hear we can find
a
as it was in ratio of 5:1 
so 
5x+1x= 6x
6*4=24l of milk was priviously

Answered by manikandanvd123
1

Answer:

Answer is 20 litre

Step-by-step explanation:

Let initially 5x+x lites of mixture pesent

now 20 litre water is added and the atio becomes 5:6. it can be expressed as

5x/(x+20)=5y/6y

25x=100x=4

then initally 5x (5X4) 20 litres of milk present

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