. a mixture has milk and water in the ratio 5:1. 20 liters of water is added and the ratio now becomes 5:6. how much milk was present in original mixture?
Answers
Answered by
0
as it is in ratio of 5:1
so
5x+1x= 6x
after 20 l of water is added
5x+6x= 11x
diff.. 11x-6x=20 l
or
11x- 6x= 5x
so
5x=20l
x=20/5
x= 4
fron hear we can find
a
as it was in ratio of 5:1
so
5x+1x= 6x
6*4=24l of milk was priviously
so
5x+1x= 6x
after 20 l of water is added
5x+6x= 11x
diff.. 11x-6x=20 l
or
11x- 6x= 5x
so
5x=20l
x=20/5
x= 4
fron hear we can find
a
as it was in ratio of 5:1
so
5x+1x= 6x
6*4=24l of milk was priviously
Answered by
1
Answer:
Answer is 20 litre
Step-by-step explanation:
Let initially 5x+x lites of mixture pesent
now 20 litre water is added and the atio becomes 5:6. it can be expressed as
5x/(x+20)=5y/6y
25x=100x=4
then initally 5x (5X4) 20 litres of milk present
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