Question

a mixture, in which 10g acetic acid (MW=60)and 18g glucose(mw=180) is dissolved in 90g water. what is the mole fraction of acetic acid in the mixture?

Answer 1

Explanation:

Correct option is

C

Benzene

mole fraction of solute =

moles of solute+moles of solvent

mole of solute

∴ mole fraction of solute ×

moles of solvent

1

mole of solvent =

molecular mass of solvent

mass of solvent

∴ mole of fraction solute ×

molecular mass of solvent

mass of solvent

1

∴ mole fraction of solute × molecular mass of solvent

Benzene has highest molecular mass

Option (c)