Math, asked by mariabernadethlastic, 11 months ago

a mixture is 25% red paint, 30% yellow paint, and 45% water. if 4 quarts of red paint are added to 20 quarts of the mixture, what is the percentage of red paint in the new mixture?

Answers

Answered by Anonymous
4

Answer:

37.5%

Step-by-step explanation:

Let 20 quarts of mixture= 100x

This mixture is having 25% red paint=25x

After adding 4 quarts of red paint

4 quarts red paint =100x/20*4=20x

Total red paint=25x+20x=45x

Total volume of mixture=100x+20x=120x

% of red paint=100*45x)/120x

=4500x/120x=37.5%


Anonymous: welcome
Answered by windyyork
2

The required percentage of red paint is 45%.

Step-by-step explanation:

Since we have given that

Total amount of mixture  = 20 quarts

Rate of red paint = 25%

Rate of yellow paint = 30%

Rate of water = 45%

So, Ratio of red, yellow and water would be

25:30:45

=5:6:9

Amount of red paint = \dfrac{1}{4}\times 20=5\ quarts

So, after adding new red paint.

Total amount of red paint becomes

4+5=9\ quarts

So, the percentage of red paint in the new mixture is given by

\dfrac{9}{20}\times 100=45\%

Hence, the required percentage of red paint is 45%.

# learn more:

A mixture is 25% red paint, 30% yellow paint, and 45% water. if 4 quarts of red paint are added to 20 quarts of the mixture, what is the percentage of red paint in the new mixture?

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