Question

$(3x ^{2} - x +4)(2x ^{2} +3x+7)+(-30x)-3$
divisor × quotient +reminder ​

Answer 1

$\mathfrak{\huge{\red{QUESTION}}}$

Given

$<font color = "blue"><marquee>ANSWER IN EXPLANATION</font color = "blue"></marquee>$

First Multiply both of the Diviser & quotiend and at last Add the remainder

Do as follows .

$(3 {x}^{2} - x + 4)(2 {x}^{2} + 3x + 7) + ( - 30x) - 3 \\ \\ = \geqslant 6 {x}^{4} + 9 {x}^{3} + 21 {x}^{2} - 2 {x}^{3} - 3 {x}^{2} \\ - 7x + 8 {x}^{2} + 12x + 28 - 30x - 3 \\ \\ = \geqslant 6 {x}^{4} + 7 {x}^{3} + 29 {x}^{2} - 3 {x}^{2} - 7x \\ + 12x + 28 - 30x - 3 \\ \\ = \geqslant 6 {x}^{4} + 7 {x}^{3} + 26 {x}^{2} + 5x + 28 \\ 30x - 3 \\ \\ = \geqslant 6 {x}^{4} + 7 {x}^{3} + 26 {x}^{2} - 25x + 25$