Question

A mixture of 125 gallons of wine and water contains 20% of water. How much water must be added to the mixture in order to increase the percentage of water to 25% of the new mixture?
a) 10 gallons b)8.5gallons c) 8gallons d)8.33gallons

Answer 1

amount of water in mixture= 125*(20/100)=25 gallons

amount of wine in mixture= 125-25=100 gallons

amount of water in final mixture = 25% of the new mixture

so , amount of wine in final mixture = 75% of the new mixture

let , new mixture= x

so amount of wine in final mixture= (75/100 )*x..................(1)

also wine amount is constant because only extra water is added

so , wine amount = 100

from equation (1)

( 75/100)*x =100

x=133.33

amount of water = 133.33-125=8.33 gallons ans.....