Question

A mixture of 140 litr is prepared by mixing wine and rum having alcohol 42.5% and 25% in ratio 2:5 .To dilute mix by 2% what amount of water is used

Answer 1

Answer:

Explanation:

.98*y= (.95)*x. (Amount of solvent will not change during the process) .02*y+10= .05*x.( Amount of solute before and after) Y=316.66. & (volume of mixture finally) x = 326.66