Math, asked by dony214, 1 year ago

A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture ?
A) 5 lit
B) 10 lit
C) 15 lit
D) 20 lit

Answers

Answered by VEDULAKRISHNACHAITAN
10

Answer:

10 liters

Step-by-step explanation:

Given the initial mixture contains 150 l of wine and water

Given the initial mixture contains 20% water,

=> 20% of 150

= 30 l

=> Out of 150 l mixture, 30 l is water and the rest 120 l is wine.

Suppose the volume of the extra water that needed to be added be 'x' liters

then, Total volume of the mixture becomes 150 + x,

wine remains same with 120 l

Also, given that water in the new mixture will be 25%

=> Wine in the new mixture should become 75%

=> 75 % of (150 + x) = 120

=>3/4(150 + x) = 120

=>450 + 3x = 480

=> 3x = 30

=> x = 10.

Thus , 10 liters of water need to be added so that water becomes 25% of the new mixture.

Answered by AJThe123456
8
Heyy mate❤✌✌❤

Number of liters of water in 150 liters of the mixture = 20% of 150

= 20/100 x 150

= 30 liters.

P liters of water added to the mixture to make water 25% of the new mixture.

Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P)

= 25/100 x (150 + P)

120 + 4P

= 150 + P

=> P = 10 liters.
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