A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture ?
A) 5 lit
B) 10 lit
C) 15 lit
D) 20 lit
Answers
Answered by
10
Answer:
10 liters
Step-by-step explanation:
Given the initial mixture contains 150 l of wine and water
Given the initial mixture contains 20% water,
=> 20% of 150
= 30 l
=> Out of 150 l mixture, 30 l is water and the rest 120 l is wine.
Suppose the volume of the extra water that needed to be added be 'x' liters
then, Total volume of the mixture becomes 150 + x,
wine remains same with 120 l
Also, given that water in the new mixture will be 25%
=> Wine in the new mixture should become 75%
=> 75 % of (150 + x) = 120
=>3/4(150 + x) = 120
=>450 + 3x = 480
=> 3x = 30
=> x = 10.
Thus , 10 liters of water need to be added so that water becomes 25% of the new mixture.
Answered by
8
Heyy mate❤✌✌❤
Number of liters of water in 150 liters of the mixture = 20% of 150
= 20/100 x 150
= 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P)
= 25/100 x (150 + P)
120 + 4P
= 150 + P
=> P = 10 liters.
Number of liters of water in 150 liters of the mixture = 20% of 150
= 20/100 x 150
= 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P)
= 25/100 x (150 + P)
120 + 4P
= 150 + P
=> P = 10 liters.
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