A mixture of 17 parts of A, 3 parts of B, and 4
parts of C weigh 72 ounces. How many
ounces of substance B are in this mixture?
Answers
Answered by
0
Answer:
0.24 ounces
Step-by-step explanation:
there is 3*b parts in the mixture weighing 72 ounces
so,
(3*b*100)/72
=75b/18
thus .. b=18/75
b=0.24 ounces
Answered by
1
Step-by-step explanation:
Total mixture contains part - 17+3+4=24
ounces per part - 72/24=3 ounces per part
then for part A - 17×3=51
for part B - 3×3=9
for part C - 4x3= 12
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