Question

a mixture of 17 parts of A, parts of 3 parts of b and 4 parts of c weigh 72 ounces. how many ounces of substance b in the mixture?​

Answer 1

Answer:

Total  Mixture Contains Parts = 17+3+4 = 24

Ounces per Part = 72/24 = 3 Ounces Per Part

Then

For Part A = 17 x 3 = 51

For Part B = 3 x 3 = 9

For Part C = 4 x 3 = 12

Step-by-step explanation:

Answer 2

The ounces of substance b in the mixture is 9 ounces

Solution:

Given that,

The mixture of 17 parts of A, parts of 3 parts of b and 4 parts of c weigh 72 ounces

Let A be 17x

Let B be 3x

Let C be 4x

Total weight = 72 ounces

Therefore,

17x + 3x + 4x = 72

24x = 72

x = 3

How many ounces of substance b in the mixture

ounces of substance B = 3x = 3(3) = 9 ounces

Thus, ounces of substance b in the mixture is 9 ounces

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