Question

A mixture of 4g of hydrogen and 8g of helium at NTP has a density of?

Answer 1

Answer:

Explanation:

Solution : 4gH2means2g-moles and8gHe means2g-moles. ρ=PMRT=(1.013×105)(3×10-3)(8.31)(273)=0.13kg/m3.

Answer 2

Answer:

0.13 kg/m³

Explanation:

Effective mass =

$M_{effective} = \frac{n_1M_1 + n_2M_2}{n_1 + n_2}\\\\= \frac{ 2(2) + 2(4)}{2 + 2}\\\\= 3g/mol$

where, n is number of moles and M is mass

$d= \frac{PM}{RT}$

substituting the values,

d = 0.13kg/m³

( P = 1.013 x 10⁵, R = 8.314, M = 3 x 10⁻³, T = 273K)