Question

The degree of dissociation of ammonium hydroxide is 0.0232 in 0.5 M solution. What will be its dissociation constant​

Answer 1

Answer:

Explanation:

Dissosciation constant K

$K = C\alpha^2$

where, C is the concentration, α is the dissosciation constant.

= 0.5 (0.0232)²

= 2.7 x 10⁻⁴

Answer 2

Answer:

Ka=C(alpha)^2

Alpha =0.0232,c=0.5

Substituting we get ans as 0.000269