A mixture of 70 l of milk and water contains 10% water. how many liters of water must be added, so that water may be 30% of the mixture?
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Answered by
4
if 70 I is having 10% water as
10/100*70= 7 l of water then
it not about 30 % of privous mixture
after adding X l fo water mixture would be 70 l + x l
(7 + x)/63 = 30/100
7 + x = 63 * 30 / 100
7 + x = 18.9
x= 11.9 l of water should be add
10/100*70= 7 l of water then
it not about 30 % of privous mixture
after adding X l fo water mixture would be 70 l + x l
(7 + x)/63 = 30/100
7 + x = 63 * 30 / 100
7 + x = 18.9
x= 11.9 l of water should be add
Answered by
3
Answer:
Step-by-step explanation:10% of 70 will be 7 liter, and that’s the quantity of water in the mixture.
Remaining 63 liter will be wine.
Let’s assume that ‘x’ liter of water is added then the equation will be like (7+x)/63=30/70
After calculating we will get the value of X as 20 liter
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