A mixture of chlorobenzene and bromobenzene forms nearly ideal solution but a mixture of chloroform and acetone does not. Why?
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An ideal solution is formed when two component which are used to form solution have almost similar interaction.Ideal solution follow Raoult's law at all constructions.So no new interaction is developed in solution after mixing hence no change of enthalpy & volume is observed in solution.In that case(math processing)Vmixing & (Math processing error)H mixing becomes zero.
When we mix chlorobenzene & bromobenmzene,no new interaction is develop in solution as chlorobenzene & bromobenzene have almost similar constituents & have similar polarities.So,there is no change in enthalpy & volume of solution after mixing.It gives ideal solution on mixing.
When we mix chlorobenzene & bromobenmzene,no new interaction is develop in solution as chlorobenzene & bromobenzene have almost similar constituents & have similar polarities.So,there is no change in enthalpy & volume of solution after mixing.It gives ideal solution on mixing.
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Answer:
as we know that enthalpy of mixing of the pure components to form the solution is zero and the volume of mixing is also zero.this is observed in the case of chlorobenzene and bromobenzene .Thus forms a ideal solution.but in case of chloroform and acetone the condition given at the first is not applicable for them as they show the opposite of the given condition.Thus the don't form a ideal solution
Explanation:
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