Question

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 k. the vapour pressure of propyl alcohol is 200 mm. if the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be

Answer 1

Total V.P of sol. , pt =  290 mm 
V.P of  propyl alcohol , p1  =  200 mm
 V.P of ethyl alcohol be p2

mole fraction of ethyl alcohol = 0.6 
mole fraction of propyl alcohol = 1 - 0.6 = 0.4

Now,

Pt = P1x1  + P2X2  =  200x0.4 + P2x0.6 
290 = 80 +0.6P2
P2 = (290 - 80) /0.6 = 210 / 0.6 = 350 mm

hence answer is 350mm

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