Question

a mixture of having 2g of hydrogen gas and 32g of oxygen gas occupies . how many volume at ntp​

Answer 1

Explanation:

2g of hydrogen occupies 22.4litres at ntp

and

32g of oxygen occupies 22.4litres at ntp

so total volume occupied is 22.4+22.4=44.8litres

44.8LITRES

Answer 2

2gm of H2. 32g of O2

Number of moles of H2=2/2

=1

number of moles of O2=32/32

=1

Volume=(number of moles of H2 &O2)×22.4(in L)

=(1+1)×22.4

=2×22.4

=44.8L