A mixture of n2 and h2 is caused to react in a closed container to form nh3 . the reaction ceases before either reactant has been totally consumed . at this stage 2mole each of n2and h2 and nh3 are lresent then find the weifjt of n2 and h2 present originally
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The reaction is that N2 + 3H2 -> 2NH3 all the states of the equations are in gaseous.
Thus from the equation we know that 1 mole of N2 reacts with 3 moles of H2 to give 2 moles of NH3. This is the condition that we get from the equation thus now to find out the initial weight of the N2 and H2.
Since at this stage 2 moles of each N2 and H2 are consumed so to produce 2 moles of NH3 we will get 1.5 moles of N2 and 4.5 moles of H2.
Thus the weight originally is (1.5 + 2) moles of N2 which is 3.5 moles of N2.
Also, (4.5+2) moles of H2 is formed originally which is 6.5 moles of H2.
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