A mixture of nitrogen and hydrogen in the ratio of 1 : 3 reaches at equilibrium with ammonia
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N2+3H2=======>2NH3.
At the start of the reaction the Pressure was'P'.
Suppose if we consider 1 mole of N2 gas and 3 moles of H2 gas was present in the beginning.(4 moles)
After the completion of 50% of the Reaction, 0.5 mole of N2, 1.5 mole of H2 and 1 mole of NH3 will be present.
So the initial 4 moles will be now (0.5+1.5+1)=3 moles will be present at the equilibrium after the completion of 50% reaction. So the Pressure at equilibrium will be 3/4 x P. = 0.75 P.
The partial pressure of Ammonia = 0.75 x (1/3) x P
= 0.25P
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