Find 20th term, sum of 20 terms of the A.P 3,15,27. . . .
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T20=a+19d=3+19×12=3+228=231
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S 20 = 10(6+228) = 2340
A 20 = 3 + 19×12 = 3+ 228 = 231
A 20 = 3 + 19×12 = 3+ 228 = 231
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