Chemistry, asked by chevynationpart1947, 1 year ago

A mixture of two gases A and B in the mole ratio 2 : 3 is kept in a 2 litre vessel. A second 3L vessel has the same two gases in the mole ratio 3 : 5. Both gas mixtures have the same temperature and same total pressure. They are allowed to intermix and the final temperature and the total pressure are the same as the initial values, the final volume being 5 litres. Given that the molar masses are M_A and M_B. What is the mean molar mass of the final mixture?
(a) \frac{5M_A+8M_B}{13}
(b) \frac{77M_A+123M_B}{200}
(c) \frac{123M_A+77M_B}{250}
(d) \frac{123M_A+77M_B}{150}

Answers

Answered by Anonymous
3

Here is your answer ⤵⤵⤵

(a) \frac{5M_A+8M_B}{13}

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Answered by Anonymous
3
 <b>
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A mixture of two gases A and B in the mole ratio 2 : 3 is kept in a 2 litre vessel. A second 3L vessel has the same two gases in the mole ratio 3 : 5. Both gas mixtures have the same temperature and same total pressure. They are allowed to intermix and the final temperature and the total pressure are the same as the initial values, the final volume being 5 litres. Given that the molar masses are M_A and M_B. What is the mean molar mass of the final mixture?
(a) \frac{5M_A+8M_B}{13}
(b) \frac{77M_A+123M_B}{200}
(c) \frac{123M_A+77M_B}{250}
(d) \frac{123M_A+77M_B}{150}


→ [B]


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