A mixture of two gases a and b is in a container at a constant temperature. Gas a is diatomic and b is moniatomic. The ratio of molecular masses is is 4. The ratio of r m s speeds is
Answers
Answered by
4
rms= √(3RT/M)
rms,a/rms,b= √(Mb/Ma)= √(1/4) =1/2.
rms,a/rms,b= √(Mb/Ma)= √(1/4) =1/2.
Similar questions