Question

a mixture of two moles of helium gas and 1 mole of a gas is kept at 300 Kelvin in a container the ratio of RMS speeds of helium and argon are

Answer 1

Answer:

RMS velocity =(3RT÷M)^1/2

M= molecular mass

T= temperature

Independent of n(no of moles)

Explanation:

two gases are at same temperature

So rms is inversely proportional to (M)^1/2

rms(He)/rms(Ar) =( M(Ar))^1/2÷(M(He))^1/2

=(40÷4)^1/2

=10^1/2

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