A monkey climbs 4 metres of a pole in 1 minute, but slips 2 metres in next minute, In how much time he will reach the top of a pole 15 meters long ? Assume that he starts from the bottom of the pole.
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Monkey is at 0 meters at 0th minute.
time t = 0 minute, height = 0
t = 1 height = 4 m
t = 2 height = 4 - 2m = 2m
t =3 h = 6 m
t =4 h = 4 m
So after t = 2 n minutes, height = 2 n meters
check when the monkey will come with in (15 - 4 ) = 11 meters.
so after t = 12 minutes, height = 12 meters
then during t = 13 minutes, monkey can climb 15 meters
time t = 0 minute, height = 0
t = 1 height = 4 m
t = 2 height = 4 - 2m = 2m
t =3 h = 6 m
t =4 h = 4 m
So after t = 2 n minutes, height = 2 n meters
check when the monkey will come with in (15 - 4 ) = 11 meters.
so after t = 12 minutes, height = 12 meters
then during t = 13 minutes, monkey can climb 15 meters
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