Question

A monkey moves 3 m towards east and 4 m towards north . Find (a) Displacement and (b) Distance from infial position .​

Answer 1

Answer:

here's ur answer....

first, the man moves 4m along East direction and then 3m along north direction. it formed a right angle triangle.

let the base be 4m and height be 3m

by Pythagoras theorem :-

= √(4²+3²)

= √(16+9)

= √25

= 5m

after going to North direction, the man climbs up a pole of height 12m. again it formed a right angle triangle and now the hypotenuse is the displacement.

now let the base be 5m and height be 12m.

by Pythagoras theorem :-

displacement = √(5²+12²)

= √(25+144)

= √169

= 13

hence, total distance covered by him = 3 + 4 + 12 = 19m and displacement = 13m

hope this helps..!!

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Answer 2

Answer:

Displacement=√9+16 ( Pythagoras theorem)

D=√25

D=5m

Distance=3+4

Dis. =7 m

Hence, the displacement is 5 m and distance is 7 m.

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