Question

a monkey of mass 20 kg is climbing on a rope is breaking strength of rope is 250 N. find the maximum acceleration with which monkey can climb on rope?​

Answer 1

QUESTION ⤵

a monkey of mass 20 kg is climbing on a rope is breaking strength of rupees 250N. find the maximum acceleration with which monkey can climb on rope?

ANSWER⤵

T of monkey=250N

T-mg=ma

T=m(g+a)

T max.= m(g+a max.)

250=20(10+a max.)

250/20=10+a max.

25/2-10/1= a max.

25-20/2= a max.

a max.= 5/2

${\huge{\boxed{\mathcal{\pink{a\:max.\:=\:2.5m sec^-1}}}}}</p><p>$

$\huge\mathfrak\star\red{hope\:it\:helps}$

Answer 2

Let the monkey climb up with acceleration a. Then tension caused in the rope will be T =

M(g+a), where M is the mass of the monkey. Maximum value of T is 25g = 20(g + a). Taking

g = 10ms

-2, it gives a = 2.5 ms

The rope will not break unto 20kg it means it is its tension.

Thus balance condition

is T-mg=ma

25g-20g= 20a (g=10) thus on solving a=50/20= 2.5m/s^ (ans)

So this monkey can have max acceleration of2.5 if he really wants to climb the tree

Let the Monkey be climbing up with an acceleration 'a'.

Tension in string =m(g+a)

=Breaking force

20(g+a)=25×g

a=g4

=104

=2.5m/s2