A monkey of mass 20kg is climbing up on the rope to balance a cage of 25kg .What is acceleration of monkey.
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2
(20+25)×10=20a
a=2.25
a= 12.5m/s2
a=2.25
a= 12.5m/s2
yogesh1010:
right answer is 2.5m/s2
but why would we add the weight of monkey with the cage
as the monkey is not in touch with the floor of the cage
Answered by
14
The rope will not break unto 20kg it means it is its tension.
Thus balance condition
is T-mg=ma
25g-20g= 20a (g=10) thus on solving a=50/20= 2.5m/s^ (ans)
So this monkey can have max acceleration of2.5 if he really wants to climb the tree
Let the Monkey be climbing up with an acceleration 'a'.
Tension in string =m(g+a)
=Breaking force
20(g+a)=25×g
a=g4
=104
=2.5m/s2
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