Question

A monkey weight 50 kg climbs up a vertical tree of height 300 metre, how much potential energy does it gain? g=9.8 metre per second square)​

Answer 1

Answer:

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Answer 2

$Given :</p><p>A body weighing 20 kg climbs up a vertical height of 50 m.</p><p>Calculate the amount of work done by it.</p><p></p><p>To Find :</p><p></p><p>Calculate the amount of work done by it.</p><p></p><p>How much potential energy does it gain in the process?</p><p></p><p>Solution :</p><p></p><p>To be Calculated :</p><p></p><p>(i)Calculate the amount of work done by him.</p><p></p><p>(ii)How much potential energy does he gain?</p><p></p><p>Formula Used :</p><p></p><p>Force ,F = m × g</p><p></p><p>Work ,W = F × d</p><p></p><p>Potential energy, P.E = m × g × h</p><p></p><p>: \implies \: \: \: \: \boxed{\sf F = m \times g }:⟹F=m×g</p><p></p><p>Substitute all Values :</p><p></p><p>\begin{gathered} : \implies \: \: \: \: \sf \: \: \: \: \: F = 20\times 9.8 \\ \\ \\ : \implies \: \: \: \: \sf \: \: \: \: \: F = 196\end{gathered}:⟹F=20×9.8:⟹F=196</p><p></p><p>Now Find The Value of Work :</p><p></p><p>: \implies \: \: \: \: \boxed{\sf W = F \times d }:⟹W=F×d</p><p>\begin{gathered}: \implies \: \: \: \: \sf W = 196\times 50 \\ \\ \\ : \implies \: \: \: \: \sf W = 9800\end{gathered}mplies \: \: \: \: \boxed{\sf P.E = m \times g \times h }:⟹P.E=m×g×h \\ begin{gathered}: \implies \: \: \: \: \sf P.E = 20\times 9.8\times 50 \\ \\ \\ : \implies \: \: \: \: \sf P.E =1000 \times 9.8 \\ \\ \\ : \implies \: \: \: \: \sf P.E =9800\end{gathered}$