Physics, asked by starsafa786, 11 months ago

A mono atomic gas at 17°C is
suddenly compressed to 1/8 of its
original volume. Then its final
temperature is
O
887°C
987°C
88°C​

Answers

Answered by davisshikhar
0

 \huge \pink{ \underline{ \pink{ \underline{{ \blue{ \bigstar \green{ \mathbb{ANSWERR}}}}}}}}

we \: knw \: tht \:  \\ PV{}^{ \gamma }  = c \\   TV {}^{ \gamma  - 1}  = c \\

T_{1} V_{1} {}^{ \gamma  - 1}  = T_{2}V _{2} {}^{ \gamma  - 1}  \\

300k \times (V) {}^{ \gamma  - 1}  = xk \times ( \frac{V}{8} ) {}^{ \gamma  - 1}

since

 \gamma for \: monoatomic \: gas \:  \\  =  \frac{5}{3}  \\  \frac{290}{x}  =  (\frac{1}{8} ) {}^{ \frac{5}{3} - 1 }  \\  \frac{290}{x}  =  (\frac{1}{8})  \frac{2}{3}  \\  \frac{290}{x}  =  \frac{1}{4}  \\ x = 290 \times 4 k = 1160 \\  = (1160 - 273) \degree \: C \\ =  887 \degree \: C

<marquee direction="right" fcolor="red" width="100%">hope it helps

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