Question

A monochromatic source of light operating at 600 watt emits 2 x1022 photons per second. Find the
wavelength of the light.​

Answer 1

Answer:

Explanation:

=> It's given here,

E = 600 watt = 600 J/s

This monochromatic source of light emits $2 * 10^{22}$ photons/ second.

∴ no of protons =2 * 10^22

E = nhc/λ

=> Wavelength of the light λ:

λ = nhc/E

= [(2*10^22)(6.626*10^-34)(3*10^8)]/ 600

= 39.756 * 10^-4 / 600

= 3975.6 * 10^-6 / 600

= 6.626 * 10^-6

= 6.626 μm

Thus, the  wavelength of the monochromatic light is 6.626 μm.​