A monostable multivibrator has r = 120k and the time delay t = 1000ms, calculate the value of c
Answers
Time delay for a monostable multivibrator, T = 1.1RC
=> C = T/(1.1R) = 1000ms/(1.1×120kΩ) = 7.57µF.
Answer:
From the given question we should calculate the capacitor(c) of the monostable multi vibrator with the help of given resistance(r) and time delay(t).Final solution of the capacitor(c) μ
Step-by-step explanation:
The Output Time Delay for monostable multi vibrator × ×
here, is the time delay and the unit is milliseconds() or second() or minute() or hour().
is the resistance and the unit is ohms(Ω) or Kilo Ohms(Ω) or Mega Ohms(Ω).
is the capacitor and the unit is farads() or Nano Farad(η) or Micro Farad(μ).
From the given data, we have resistor value() and time delay(). So the formula for the capacitor() is,
×
Already we have the following values and Ω
So that,
here milliseconds denoted as .kilo ohms denoted as .
Now we get the following values,
×
in the numerator can be written as ×.
×
Now we add and and we will get .
×
×
×
× ×
×
capacitor μ