Question

A month is selected at random in a year. The probability that it is March or October, is
A. 1/12
B. 1/6
C. 3/4
D. None of these

Answer 1

Given : A month is selected at random in a year .

To find :  The probability that it is March or October, is

Solution :

Total months in a year = 12  

Total number of outcomes = 12

Let E = Event of selecting that the month is March or October

Favourable outcomes =  March or October  

Number of favourable outcomes to E = 2

Probability P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 2/12 = 1/6

Hence, the probability of selecting that the month is March or October , P(E) = 1/6  .

Option (b) ⅙ is correct.

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Some more questions :  

From the letters of the word ''MOBILE", a letter is selected. The probability that the letter is a vowel, is

(a)$\frac{1}{3}$

(b)$\frac{3}{7}$

(c)$\frac{1}{6}$

(d)$\frac{1}{2}$

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A number is selected from first 50 natural numbers. What is the probability that it is a multiple of 3 or 5?

(a)$\frac{13}{25}$

(b)$\frac{21}{50}$

(c)$\frac{12}{25}$

(d)$\frac{23}{50}$

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Answer 2

Answer:

1/6

Step-by-step explanation:

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