A mooncake with two egg yolks costs $2 more than
a mooncake with one egg yolk. The cost of
6 mooncakes with two egg yolks and 5 mooncakes
with one egg yolk is $130.80. Find the cost of
a mooncake with two egg yolks.
Answers
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The cost of one mooncake with two egg yolks is ₹12.80.
12.80.Step-by-step explanation:Let the cost of the mooncake with two egg yokes be ₹ “x” and that of the mooncake with 1 egg yolk be ₹ “y”.
“y”. It is given that the mooncake with two egg yolks costs ₹2 more than the mooncake with one egg yolk, therefore the eq. is,
more than the mooncake with one egg yolk, therefore the eq. is,x = 2 + y
more than the mooncake with one egg yolk, therefore the eq. is,x = 2 + y⇒ x – y = 2 ……. (i)Also given, the cost of 6 mooncakes with two egg yolks and 5 mooncakes with one egg yolk is ₹230.8, therefore the eq. is,
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.8
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + -
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8------------------------
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8------------------------∴ y = 118.8/11 = 10.8
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8------------------------∴ y = 118.8/11 = 10.8Substituting y = 10.8 in eq. (i), we get
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8------------------------∴ y = 118.8/11 = 10.8Substituting y = 10.8 in eq. (i), we getx – y = 2
30.8, therefore the eq. is,6x + 5y = 130.8 ……. (ii)Now,Multiplying by 6 throughout the eq. (i) and then subtracting from eq. (ii), we get6x + 5y = 130.86x – 6y = 12- + ------------------------ 11y = 118.8------------------------∴ y = 118.8/11 = 10.8Substituting y = 10.8 in eq. (i), we getx – y = 2⇒ x = 2 + 10.8 = ₹12.8
12.8Thus, the cost of a mooncake with two egg yolks is ₹12.8.